Question

$\huge{\mathcal{\purple{Question for Brainly Stars and Moderator}}}$​

Answer 1

$\huge{ \underline{ \overline{ \mid{ \mathfrak{ \purple{ \: \: SOLUTION \: \: } \mid}}}}}$

$\underline{ \mathfrak{ \: \: We \: \: know \: \: that, \: \: }} \\ \\ \: \: \: \: \: \: \: \: \sf{ \red{ \star \: \: Linear \: \: pair \: \: of \: \: angles \: \: must \: \: add \: \: up \: \:} }\\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{\red{ to \: \: 180 \degree.}}$

$\underline{ \text{ \: In \: the \: diagram, \: }} \\ \\ \: \: \: \: \: \: \: \bf{\angle BAC + 110 \degree = 180 \degree \: \: \: \: [Linear \: \: pair]} \\ \\ \bf{\implies \angle BAC = 180 \degree - 110 \degree} \\ \\ \: \: \: \: \: \: \: \: \: \: \bf{\therefore \: \pink{\angle BAC = 70 \degree}}$

$\mathfrak{Again,} \\\: \: \: \: \: \: \underline{ \mathfrak{ \: \: We \: \: know \: \: that, \: \: }} \\ \\ \: \: \: \: \: \: \: \: \: \sf{ \red{ \star \: \: An \: \: exterior angle \: \: of \: \: a \: \: triangle \: \: is \: \: }} \\ \: \: \: \: \: \: \: \: \: \sf{ \red{ equal \: \: to \: \: the \: \: sum \: \: of \: \: the \: \: opposite \: \: }} \\ \: \: \: \: \: \: \: \: \: \: \: \: \sf{ \red{ interior \: \: angles.}}$

$\text{ \underline{ \: In \: the \: diagram, \: }} \\ \\ \: \: \: \: \: \: \bf{\angle BAC + \angle ABC = 120 \degree} \\ \\ \bf{\implies 70 \degree + x \degree = 120 \degree} \\ \\ \bf{\implies x \degree = 120 \degree - 70 \degree} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \bf{ \therefore \: \: \pink{x \degree = 50 \degree}}$

$\huge{ \underline{ \tt{ \blue{ \: Value \: \: of \: \: x = 50 \degree \: }}}}$

Answer 2

Answer:

hloo user

here is your answer

110+y =180(linear pair)

y = 180-110

=70

z+ 120= 180(linear pair)

z=180-120

=60

Now in triangle X+ y+ z = 180( angle sum property)

X+70+60=180

X+130=180

X=180-130

=50

Hope that it's helpful to you