Question

$\huge\mathfrak\red {Question}$

FIND THE ACTUAL LOWER AND UPPER-CLASS LIMITS ,ALSO THE CLASS MARKS OF THE CLASSES: 1.1-2.0 , 2.1-3.0 AND 3.1-4.0

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Answer 1

Answer:

HEY!!! THERE

Step-by-step explanation:

In the case of frequency 1.1 -2.0 the lower case limit is 1.1 , upper case limit is 2.0 and classmark is ↓

1.1 + 2.0 = 1.55

2

In the case of frequency 2.1 - 3.0 the lower case limit is 2.1 and upper case limit is 3.0, and classmark ↓

2.1 + 3.0 = 2.55

2

In the case of frequency 3.1 - 4.0 the lower case limit is 3.1 and the upper case limit is 4.0 ,and the classmark is↓

3.1 + 4.0 = 3.55

2

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Answer 2

Question :

FIND THE ACTUAL LOWER AND UPPER-CLASS LIMITS ,ALSO THE CLASS MARKS OF THE CLASSES: 1.1 - 2.0, 2.1 - 3.0 AND 3.1 - 4.0 ?

Concept :

Upper limit is highest value of the class interval and the actual upper limit is obtained by adding 0.5 to the highest number if number is represented as whole number or add 0.05 to the highest number if the number is represented as decimal.

Solution :

$\sf \: d = \frac{Lower \: Limit − upper \: Limit \: Of \: Previous \: Column}{2}$

$\implies\sf\frac{2.1 - 2.0}{2} = 0.05$

$\pink{ \sf \: Class \: mark \: is \: the \: mid \: point \: of \: the \: class \: interval.}$

Given,

Class intervals are 1.1 − 2.0, 2.1 − 3.0, 3.1 − 4.0.

Since, the intervals are represented in decimal, we add and subtract 0.05 to get the actual limits.

$\sf \: For \: class \: interval 1.1−2.0,$

$\sf \: class \: mark \: is \: \frac{1.1 + 2.0}{2} = \sf\frac{3.1}{2} = 1.55$

$\sf \: Actual \: upper \: limit \: is  \: 2.0 \: + \: 0.05 \: = \: 2.05  \: and \: actual \: lower \: limit \: is \:  1.1 \: − \: 0.05=1.05$

$\green{\boxed{ \sf Similarly \: for \:  2.1−3.0,}}$

$\sf \: Class \: mark \: is \: \frac{2.1 + 3.0}{2} = 2.55$

$\sf \: Actual \: upper \: limit \: is \: 3.0+0.05=3.05 \: and \: actual \: lower \: limit \: is \: 2.1−0.05=2.05$

$\purple {\boxed{ \sf \: Similarly \: for \: 3.1−4.0,}}$

$\sf \: Class \: mark \: is \: \frac{3.1-4.0}{2} =3.55$

$\sf \: Actual \: upper \: limit \: is \: 4.0+0.05=4.05 \: and \: actual \: lower \: limit \: is \: 3.1−0.05=3.05$

$\sf \: Therefore, \: actual \: upper \: limits \: are \: 2.05,3.05,4.05\: Actual \: lower \: limits \: are \: 1.05,2.05,3.05$

$\underline{ \boxed{ \sf{ \red{Class \: marks \: are \: 1.55,2.55,3.55}}}}$