Q1. Find the height of cuboid whose volume is 60 m and its breadth is 4 m and length is 5 m.
Q2. The ratio of length and breadth of a table is 2:3 and perimeter of table is 150 cm². Find the area
Q3. The length of a rectangle was 4 times of its breadth. Perimeter of lawn is 640 m.
Q4. The length was 3 times more than breadth. Area of rectangle is 108 m². Find its perimeter
Q5. The perimeter of rectangle is 50 cm and its length is 18 cm. Find its breadth.
Q6. Find the CSA of cone whose radius is 7 cm and its slanght height is 10 cm. [Take π = 22/7]
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Answer:
Answer 1) Length=5m Breadth=4m Volume=60 m height=?
Length (L)×Breadth (B) ÷Volume (V)=height
5m×4m÷60m=height
20 upon 60= 0.6m³
Answer 5) P= 50 cm L=18 cm B=?
L×B=P
B=P/L
B=50cm/18cm
B=2.8cm²
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