Question

$\Huge{\underline{\sf Question:-}}$


$\sf 2^{3x+1}=256$

Solve for x

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Answer 1

Step-by-step explanation:

${2}^{3x + 1} = 256 \\ now \: we \: know \: that \\ 256 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \\ 256 = {2}^{8} \\ now \\ {2}^{3x + 1} = 256 \\ {2}^{3x + 1} = {2}^{8} \\ on \: comparing \: exponent \\ 3x + 1 = 8 \\ 3x = 8 - 1 \\ 3x = 7 \\ x = \frac{7}{3}$