One ounce of solution X contains only ingredients a and b in a ratio of 2:3. One ounce of solution Y contains only ingredients a and b in a ratio of 1:2. If solution Z is created by mixing solutions X and Y in a ratio of 3:11, then 2520 ounces of solution Z contains how many ounces of a?
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7
Answer:
876 ounces
Step-by-step explanation:
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Answer:
Hey candy clause
Step-by-step explanation:
2520 oz /3=840=the ounces of a
the ounces of a= 840 ounces.
One ounce of solution Y contains a and b in a ratio of 1:2.
1:2*840=840:1680
the ounces of b=1680
y oz solution =1680
x oz solution =840
z oz solution=2520
z oz solution=y oz solution +x oz solution
2520/3=840 (the amount of x ounces solution)
2520 ounces of solution Z/x (3)=the ounces of a.
(Y=a:b = 1:2)
1:2*840=840:1680=x:y
y*840=the ounces of x and y’s solution
Hope it helps u
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