Math, asked by Anonymous, 10 months ago

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One ounce of solution X contains only ingredients a and b in a ratio of 2:3. One ounce of solution Y contains only ingredients a and b in a ratio of 1:2. If solution Z is created by mixing solutions X and Y in a ratio of 3:11, then 2520 ounces of solution Z contains how many ounces of a?





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Answers

Answered by mayank1702
7

Answer:

876 ounces

Step-by-step explanation:

Hope you understand it....

Attachments:
Answered by shanmukee59
1

Answer:

Hey candy clause

Step-by-step explanation:

2520 oz /3=840=the ounces of a

the ounces of a= 840 ounces.

One ounce of solution Y contains a and b in a ratio of 1:2.

1:2*840=840:1680

the ounces of b=1680

y oz solution =1680

x oz solution =840

z oz solution=2520

z oz solution=y oz solution +x oz solution

2520/3=840 (the amount of x ounces solution)

2520 ounces of solution Z/x (3)=the ounces of a.

(Y=a:b = 1:2)

1:2*840=840:1680=x:y

y*840=the ounces of x and y’s solution

Hope it helps u

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