Question

$if \: p = 5 - 2 \sqrt{6} \: then \: find \: {p}^{2} + 1 \div {p}^{2}$
​

Answer 1

Answer:

please let me know if you need anything else from me please let me know if you need anything else from me please

Answer 2

Step-by-step explanation:

${p}^{2} + 1 = ( {5 - 2 \sqrt{6} )}^{2} + 1\\ = 25 + 24 - 20 \sqrt{6} + 1 \\ = 50 - 20 \sqrt{6 } \\ = 5(10 - 4 \sqrt{6} ) \\ now \: \frac{ {p }^{2} + 1}{ {p}^{2} } = \frac{5(10 - 4 \sqrt{6)} }{49 - 20 \sqrt{6} }$

you can solve further by rationalizing ........