Question

$if \: p = 99 \: p{p2 + 3p + 3)| |?|$
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Answer 1

$\huge{\mathfrak{\underline{Answer :}}} \\ \\ \underline{\boxed{\sf{Value \: of \: p(p^2 + 3p + 3) \: is \: 999999.}}} \\ \\ \huge{\mathfrak{\underline{Step-by-Step \: Explanation :}}} \\ \\ \sf Given, \: p(p^2 + 3p + p) \\ \sf \implies p^3 + 3p^2 + 3p \\ \sf \implies p^3 + 3p^2 + 3p + 1 - 1 \\ \sf \implies {(p + 1)}^3 - 1 \\ \sf \implies {(99 + 1)}^3 - 1 \\ \sf \implies 100^3 - 1 \\ \sf \implies 1000000 - 1 \\ \sf \implies 999999 \\ \\\large{\textbf{\underline{Thanks ..!!!}}}$