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Answered by
0
Hi,
Here's the solution :-
x = 2 + root 3
=>x^2 =[ 2 + root 3 ] ^2
=> x^2 = 5 + 4 root 3
=> x^2 + 1/x^2 = 5 + 4 root 3 + 1/(5 + 4 root 3)
Hope it helps ^_^
Here's the solution :-
x = 2 + root 3
=>x^2 =[ 2 + root 3 ] ^2
=> x^2 = 5 + 4 root 3
=> x^2 + 1/x^2 = 5 + 4 root 3 + 1/(5 + 4 root 3)
Hope it helps ^_^
usha40444:
but the answer is 14
Answered by
2
Hey friend
Here is your answer
x=2+√3
1/x=1/(2+√3)
1/x=(2-√3)/[(2+√3)(2-√3)]
1/x=(2-√3)/(2²-(√3)²)
1/x=(2-√3)/(4-3)
1/x=2-√3
Value of x²+(1/x²)
=x²+(1/x²)
=(2+√3)²+(2-√3)²
=4+3+2√3+4+3-2√3
=7+7
=14
HOPE THIS HELPS YOU
Here is your answer
x=2+√3
1/x=1/(2+√3)
1/x=(2-√3)/[(2+√3)(2-√3)]
1/x=(2-√3)/(2²-(√3)²)
1/x=(2-√3)/(4-3)
1/x=2-√3
Value of x²+(1/x²)
=x²+(1/x²)
=(2+√3)²+(2-√3)²
=4+3+2√3+4+3-2√3
=7+7
=14
HOPE THIS HELPS YOU
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