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Answered by
200
◀ HEY THERE!◀
◀ Question: ◀
→ A student is ranked 19th in a class of 50.what Is his rank from the last?
Method of Solution:
→ Given:
⇒ Total Student in the Class = 50
⇒ Student rank = 19th
→ To Find:
⇒ Rank From the last = ?
There are two method to solve this type of Questions.
→ Method l : (Solving by Alternative Method)
→ Let the rank from last or end be x ,
Rank From Start + Rank From Last = Total Number of Students + 1
⇒ 19 + x = 50+1
⇒ 19+x = 51
⇒ x =51-19
⇒ x = 32
→ Therefore, 32th rank from from the last.
◀ Method ll: ◀
Given:
⇒ Total Student in the Class = 50
⇒ Student rank = 19th
Lets find How many students behind him/she,
Total Student- Student Rank
⇒ = 50- 19
⇒ 31
→ Concept: It's means 31 Student behind that Student.
Student from end + 1
⇒ 31 + 1
→ ◀ Thus ,it meant 32 Student from the last.◀
sanjana854:
hey aman
Answered by
69
As 19 + x( rest students) = 50
x= 31
So rank of 19 th student from the last is 31 + 1 = 32 th rank
OR
A student is at 19 th position
and total 50 students
As we know if x1,x2,.........xn students are there , obviously there are n students OR
so to find no of students it's ( xn - x1 +1)
So to find position of 19 th student from last
simply calculate no of students from 19 th position
19, 20,.........50
So it's (50-19) + 1 = 31+ 1 = 32
⚡⚡⚡⚡Dhruv⚡⚡⚡⚡⚡⚡⚡
x= 31
So rank of 19 th student from the last is 31 + 1 = 32 th rank
OR
A student is at 19 th position
and total 50 students
As we know if x1,x2,.........xn students are there , obviously there are n students OR
so to find no of students it's ( xn - x1 +1)
So to find position of 19 th student from last
simply calculate no of students from 19 th position
19, 20,.........50
So it's (50-19) + 1 = 31+ 1 = 32
⚡⚡⚡⚡Dhruv⚡⚡⚡⚡⚡⚡⚡
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