Question

$\left[ \iota^{18} + \left(\dfrac{1}{\iota}\right)^{25}\right]^3$ का मान ज्ञात कीजिए l

Answer 1

sorry l don't understand maths in hindi

SORRY!!!!!!!!!

Answer 2

$\left[ \iota^{18} + \left(\dfrac{1}{\iota}\right)^{25}\right]^3$ का मान ज्ञात कीजिए l

${i}^{2} = - 1 \\ \\ {i}^{4} = 1$
$\left[ i^{4 \times 4 + 2} + \left(\dfrac{1}{i}\right)^{4 \times 6 + 1}\right]^3 \\ \\ = \bigg[ i^{4 \times 4} \times {i}^{2} + \frac{1}{ {i}^{4 \times 6} \times i} \bigg]^3 \\ \\ = \bigg[ - 1+ \frac{1}{i} \bigg]^3 \\ \\ = > {( - 1 - i)}^{3} = {( - 1)}^{3} + {( - i)}^{3} + 3 {( - 1)}^{2} ( - i) + 3( - 1)( { - i)}^{2} \\ \\ = > - 1 + i - 3i + 3 \\ \\ = > 2 - 2i$