Question

$N_2(g) + 3H_2(g) \to 2NH_3(g) ; \Delta_rH^\Theta = -92.4 kJ mol^{-1}$ NH₃ गैस की मानक विरचन एन्थैल्पी क्या है?

Answer 1

Answer:

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Explanation:

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Answer 2

$NH_3(g)$ का  मानक विरचन एन्थैल्पी $= -46.2 kJ mol^{-1}$

Explanation:

प्रश्न में दिया हाउ समीकरण  , $N_2(g) + 3H_2(g) \rightarrow 2 NH_3(g) ; \Delta_r H^{\circ}= -92.4 kJmol^{-1}$

चुकि , मानक विरचन एन्थैल्पी का मान हमेशा 1 मोल के लिए ज्ञात होता है तथा  1  मोल $NH_3(g)$ के लिए  , समीकरण कुछ इस प्रकार से होगा ;

            $\frac{1}{2} N_2 (g) + \frac{3}{2} H_2 (g) \rightarrow NH_3(g)$

इसलिए ,

$NH_3(g)$ का  मानक विरचन एन्थैल्पी $= \frac{1}{2} \times \Delta_r H^{\circ}$$= \frac{1}{2} \times (-92.4 kJ mol^{-1} )$

                                                      $= -46.2 kJ mol^{-1}$

अतः $NH_3(g)$ का  मानक विरचन एन्थैल्पी $= -46.2 kJ mol^{-1}$