Question

$p(x) = x {}^{3 } - 2x {}^{2} + mx - 4 \\ p(1) = 1 {}^{3} - 2 \times 1 {}^{2} + m \times 1 - 4 = 0$
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Answer 1

Answer:

$\huge{\boxed{\boxed{\sf{m=5}}}}$

Step-by-step explanation:

$\huge{\boxed{\boxed{\underline{\sf{SOLUTION-}}}}}$

$p(x) = {x}^{3} - 2 {x}^{2} + mx - 4 \\ p(1) = {1}^{3} - 2 \times {1}^{2} + m \times 1 - 4 = 0 \\ =) 1 - 2 + m - 4 = 0 \\ = )1 - 6 + m = 0 \\ = ) - 5 + m = 0 \\ = )m = 5$

$\huge{\boxed{\boxed{\sf{m=5}}}}$