Question

a vessel of capacity 600 cm3 contains hydrogen gas at a pressure of 330 CM of HG what will be the pressure of hydrogen gas when the vessel is connected to another vessel of 300 cm3 capacity (By boyle's law) (ans: 220 cm Hg)​

Answer 1

Answer:

· P¹= 304 Hg V¹= 600cm³ V²= 600+ 300= 900cm³ P²=? ... gas, when the vessel is connected to another vessel of 300 cm3 capacity? Ans is given:202.67cm of Hg.

Explanation:

Answer 2

220 cm Hg

Boyle's law, also known as the Boyle–Mariotte law or Mariotte's law, is an experimental gas law that states that as the volume of a container rises, the pressure of a gas tends to decrease.

The pressure (p) of a given quantity of gas changes inversely with its volume (v) at constant temperature, according to this empirical relationship proposed by scientist Robert Boyle in 1662.

According to Boyle's Law,

For a constant Temperature,

p1*v1 = p2*v2

∴ 330 * 600 = p2 * (600+300)

∴ p2 = 220 cm Hg