a vessel of capacity 600 cm3 contains hydrogen gas at a pressure of 330 CM of HG what will be the pressure of hydrogen gas when the vessel is connected to another vessel of 300 cm3 capacity (By boyle's law) (ans: 220 cm Hg)
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Answer:
· P¹= 304 Hg V¹= 600cm³ V²= 600+ 300= 900cm³ P²=? ... gas, when the vessel is connected to another vessel of 300 cm3 capacity? Ans is given:202.67cm of Hg.
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220 cm Hg
Boyle's law, also known as the Boyle–Mariotte law or Mariotte's law, is an experimental gas law that states that as the volume of a container rises, the pressure of a gas tends to decrease.
The pressure (p) of a given quantity of gas changes inversely with its volume (v) at constant temperature, according to this empirical relationship proposed by scientist Robert Boyle in 1662.
According to Boyle's Law,
For a constant Temperature,
p1*v1 = p2*v2
∴ 330 * 600 = p2 * (600+300)
∴ p2 = 220 cm Hg
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