Draw a line AB, take two points C and D. C above the line AB and D below the line.through C and D
construct lines CX and DY parallel to AB. Can you say these CX||AB||DY ?
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Step I: Draw a line AB and take two points C and E on its opposite sides.
Step II: With C as centre, draw an arc PQ, which intersects line AB at P and Q.
Step III: Without disturbing the compass and taking P and Q as centres, construct two arcs, such that they intersect each other at H.
Step IV: Join points H and C. HC crosses line AB at D. Thus we got CD⊥AB.
The diagram is shown in the above image.
Step V: Similarly, take E as centre and draw an arc RS.
Step VI: Taking R and S as centres, draw two arcs which intersect each other at G.
Step VII: Join points G and E. GE crosses AB at F.
We have EF⊥AB.
Refer above image. 2
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