Question

${ \sec}^{2} (1 + sin) (1 - sin) = k \: find \: the \: value \: of \: k$

Answer 1

Answer :

k=1

Explanation:

${ \sec}^{2} (1 + sin) (1 - sin) = k \: find \: the \: value \: of \: k$

sec²A (1+sinA)(1-sinA)=k

=> sec²A[ 1² - sin²A ] = k

=> sec²Acos²A =k

=> (1/cos²A)(cos²A) = k

=> 1 = k

Therefore,

k = 1

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