Question

$secx - tanx \div secx + tanx = 1 - 2secxanx + 2tan {x}^{2}$
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Answer 1

Step-by-step explanation:

= secx - tanx / secx + tanx = 1-2secx tanx + 2tanx^2

= secx tanx - sec＾2x / secx tanx + sec*2x = 1-2( secx sec*2x + tan*2x secx )

= tanx - sec/ tanx + secx = secx - 2sec*2+tan*2x

= tanx- secx= secx tanx-2sec*2x tanx+tan*3- sec*2x-2sec*3x + secxtan*2x

= 2 secx,.tanx ( 1-secx) + tan*3x - tanx -3sec*3x+ secx