Question

$\sqrt{3 } + 1 \div 2 \sqrt{2}$ rationalise the given number.​

Answer 1

Answer:

x= sqrt{3+1}/2sqrt{2-sqrt 3}

= sqrt(4) / 2 sqrt{2-sqrt 3}

= 2/2 sqrt{2-sqrt3}

.cancelled 2

= 1/sqrt{2-sqrt 3}

now rationalise

:x= sqrt{2+sqrt3}/ sqrt{2-sqrt3}{2+sqrt}

sqrt of num. and denom. will be cancelled

= {2+sqrt 3}/{4-3}

.(a+b)(a-b)=a.sq.-b.sq.}

the denominator after solving is 1

::x=2+sqrt 3

Step-by-step explanation:

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Answer 2

Answer:

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