Question

$\sqrt{(3/5)^1^-^2^x } = 125/27$

Answer 1

here is ur answer:

$\sqrt{ { (\frac{3}{5} )}^{(1 - 2x)} } = \frac{125}{27} \\ \\\sqrt{ { (\frac{3}{5} )}^{(1 - 2x)} } = {(\frac{5}{3} )}^{3} \\ \\ \sqrt{ { (\frac{3}{5} )}^{(1 - 2x)} } = { (\frac{3}{5} )}^{ (- 3)} \\ \\ { (\frac{3}{5} )}^{(1 - 2x)} = {{ (\frac{3}{5} )}^{ (- 3)} }^{(2)} \\ \\ { (\frac{3}{5} )}^{(1 - 2x)} = {\frac{3}{5} }^{(2 \times - 3)} \\ \\ { (\frac{3}{5} )}^{(1 - 2x)} = {\frac{3}{5} }^{ - 6} \\ \\ on \: comparing \: both \: sides \\ \\ 1 - 2x = - 6 \\ \\ 1 + 6 = 2x \\ \\ 7 = 2x \\ \\ x = \frac{7}{2}$

hope it helps you!