Question

$\sqrt{x} + y = 11 \\ x + \sqrt{y} = 11$
find the value of x​

Answer 1

Answer:

=a>0⇒x=a2x=a>0⇒x=a2

y√=b>0⇒y=b2y=b>0⇒y=b2

x−−√+y=11x+y=11

a+b2=11a+b2=11

a=11−b2a=11−b2

x+y√=7x+y=7

a2+b=7a2+b=7

(11−b2)2+b=7(11−b2)2+b=7

b4−22b2+b+114b4−22b2+b+114

(b−3)(b3+3b2−13b−38)=0(b−3)(b3+3b2−13b−38)=0

b3+3b2−13b−38=0b3+3b2−13b−38=0

b≈−3.7793<0b≈−3.7793<0

b≈−2.8051<0b≈−2.8051<0

b≈3.5844→a≈−1.8479<0b≈3.5844→a≈−1.8479<0

Therefore :

b−3=0⟶b=3

hope its help full please make me brainliest