BC is a tower, B is its base. A is a point on a horizontal line passing through B, the
angle of elevetion of C from A is 60° From another point Don AB, the angle of
elevation is found to be 30°, then BD=
HELP ME
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Answered by
2
Answer:
h=asinθ=2asinθcosθ⟶1
In △PBC, by sine rule
sin(π−3θ)
a
=
sinθ
b
∴
b
a
=
sinθ
3sinθ−4sin
3
θ
∴sin
2
θ=
4b
3b−a
&cos
2
θ=
4b
a+b
Putting in equation 1
h=
2b
a
(a+b)(3b−a)
solution
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