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Answer 1

hope this helps u....

Answer 2

Answer:

6.125 cm²

Step-by-step explanation:

Given, AB = BC = 3.5 cm, DE = 2 cm.

From figure:

DC = DE + EC

     = 2 + 3.5

     = 5.5 cm.

Area of trapezium ABCD:

= (1/2) * (Sum of parallel sides) * Altitude

= (1/2) * (AB + DC) * BC

= (1/2) * (3.5 + 5.5) * 3.5

= 15.75 cm²

Area of the Quarter circle:

= (θ/360) * πr²

= (90/360) * π * (3.5)²

= (1/4) * π * 12.25

= 269.5/28

= 9.625 cm²

∴ Area of remaining cardboard

Area of trapezium - Area of quadrant

= 15.75 - 9.625

= 6.125 cm²

Therefore, Area of remaining cardboard = 6.125 cm²

Hope it helps!