Question

$the \: value \: of \: \sqrt{ \sqrt{ \sqrt{ \sqrt{ \sqrt{ \frac{ \sqrt{6} }{?} } } } }$
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Answer 1

Answer:

not clear pls send again

Answer 2

Answer:

Sorry

Step-by-step explanation:

Can't understand your Question

\sf{\huge{\underline{\orange{Given :-}}}}

Given:−

A hollow glass stopper weights 23.4gf in air and 3.9 gf in water.

The relative density of glass is 2.6.

\sf{\huge{\underline{To\:Find :-}}}

ToFind:−

The volume of the glass.

The volume of the water displaced.

The volume of the hollow space in the stopper

\sf{\huge{\underline{\pink{Formula\:Used:-}}}}

FormulaUsed:−

★ Density = \dfrac{mass}{volume}

volume

mass

\sf{\huge{\underline{\green{Solution:-}}}}

Solution:−

Case 1 :-

The volume of the glass.

Volume = Total mass / relative density

➝ 23.4 +3.9/ 2.6

➝ 27.3/2.6

➝ 10.5 cm³

Case 2 :-

The volume of the water (Its for medium warer ) (V2)

We have, 23.4gf in air

We know,

Density = \dfrac{mass}{volume}

volume

mass

➝ p = \dfrac{m}{v} p=

v

m

p = 2.6

m = 3.9 gf

➝ 2.6 = \dfrac{3.9 }{v} 2.6=

v

3.9

➝ v = \cancel {\dfrac{3.9 }{2.6}} v=

2.6

3.9

➝ 1.5 cm³

Case 3 :-

The volume of the hollow space in the stopper.

➝ Total volume - Volume of water

➝ 10.5 cm³ - 1.5 cm³

➝ 9 cm³

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