Question

$\tt{}4 \times \sqrt[3]{64}$

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Answer 1

$If ,</p><p></p><p>log_{a}(b) = nloga(b)=n</p><p></p><p>then ,</p><p></p><p>{a}^{n} = ban=b</p><p></p><p>=> so , according to the above concept ,</p><p></p><p>=> 4³ = 64</p><p></p><p>log_{4}(64) = 3log4(64)=3</p><p></p><p>$

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Answer 2

Answer:

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