Question

$x { }^{2} - 10x + 24 + 6y - 9y {}^{2}$
Sulph And help me​

Answer 1

Step-by-step explanation:

what I had to do answer and repost it again I will answer you as you had stated

repost it

Answer 2

$\huge{ \underline{ \overline{ \mid{ \mathfrak{ \purple{ \: \: SOLUTION\: \: } \mid}}}}}$

$\: \: \: \: \: \: \tt{ \red{x {}^{2} - 10x + 24 + 6y - 9y {}^{2} }}\\ \\ \tt{ \blue{= x {}^{2} - 10x + (25 - 1) + 6y - 9y {}^{2} }} \\ \\ \tt{ \pink{=x {}^{2} - 10x + 25 - 1 + 6y - 9y {}^{2} }}\\ \\ \tt{ \green{=x {}^{2} - 10x + 25 - 9y {}^{2} + 6y - 1}} \\ \\ \tt{ \purple{= (x {}^{2} - 10x + 25) - (9y {}^{2} - 6y + 1)}} \\ \\ \tt{=\{(x) {}^{2} - 2 \times x \times 5 + (5) {}^{2} \} - }\\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{\{ (3y) {}^{2} - 2 \times 3y \times 1+( 1) {}^{2} \} }\\ \\ \tt{ \purple{=\{ (x - 5) {}^{2} \} - \{ (3y - 1) {}^{2} \} }}\\ \\ \tt{ \green{= \{(x - 5) + (3y - 1) \} \{(x - 5) - (3y - 1) \} }}\\ \\ \tt{ \pink{= \{x - 5 + 3y - 1 \} \{x - 5 - 3y + 1\}}} \\ \\ \tt{ \blue{=(x + 3y - 5 - 1)(x - 3y - 5 + 1)}} \\ \\ \tt{ \red{=\underline{\: (x + 3y - 6)(x- 3y - 4) \: }}} \:$

$\star \: \: \: \: \underline{ \purple{ \text{ \: FORMULA \: \: USED : - \: }}}$

$\bold{1. \: (a + b) {}^{2} = a {}^{2} + 2ab + b {}^{2}} \\ \\ \bold{2. \: (a - b) {}^{2} = a {}^{2} - 2ab + b {}^{2}} \\ \\ \bold{3. \: a {}^{2} - b {}^{2} =( a + b)(a - b)}$