Math, asked by Anonymous, 1 year ago

x^2+18x+30=2\sqrt{x^2+18x+45}
What is the real value of x?
There will be 2 real values. Multiply the values then tell me the answer .


Anonymous: the easiest question it is really a class 9 quadratic equation question!

Answers

Answered by purushottamkumar67
10
HIII

FIND YOUR ANSWER HERE


HOPE THIS HELPS YOU
Attachments:

Anonymous: ans is 20 correct!
Anonymous: but ur process u did not show after (u+6)(u-10)=0
Anonymous: its ok bro ^_^ thnx
Answered by mkrishnan
5

Answer:

Step-by-step explanation:

take y = x^2 +18x +30

then the equation is changed as

       y = 2√[y+15 ]  so y should positive

y^2 = 4[y+15]

y^2 =4y +60

y^2 - 4y -60 = 0

[y-10] [y+6 ]= 0

y = 10 or y = -6

but if  y = -6  then y = 2√[y+15]   gives -6 = 6  

so we take y =10 only

x^2 +18x +30 =10

x^2 +18x +20 =0

x = [-18 +-√[324-80]]/2

          = [-18 +-√244]/2

             = [-18+-2√31]/2

                =-9+-√31

Similar questions