![{x }^{2} + 2x + 21 = 0 {x }^{2} + 2x + 21 = 0](https://tex.z-dn.net/?f=+%7Bx+%7D%5E%7B2%7D++%2B+2x+%2B+21+%3D+0)
find the value of x ?
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2472-267&2666_2677:27+
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