Question

$x {}^{2} - 4 \sqrt{2x } + 6 = 0$
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Answer 1

Step-by-step explanation:

Given equation is x²-4√3x+6=0

=>x²-4√2x+6=0

=>x²-√2x-3√2x+(√2)(3√2)=0

=>x(x-√2)-3√2(x-√2)=0

=>(x-√2)(x+3√2)=0

(x-√2)=0 (or)(x-3√2)=0

=>x=√2 and x=3√2

Therefore x=√2 and 3√2

Roots of the given equation are √2 and 3√2