Question

$x {}^{2} + x - 20 = 0$
$2y {}^{2} + 27y + 13 = 0$
$5m {}^{2} = 22m + 15$
ye 3 sums koi bata do..

Answer 1

Ur answer is in attachment ...

I HOPE IT WILL HELP YOU☺️✌️


Thank you☺️✌️

Answer 2

✴✴$\color{gold}{ \bf{HEY \: FRIENDS!!}}$✴✴

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✴✴$\color{orange}{ \bf \underline{Here \: is \: your \: answer ↓}}$⬇⏬⤵

⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇

▶⏩$\color{grey}{ \boxed{FACTORISE \: the \: following:-)}}$

↪➡$\color{red}{ \bf{(1). \: {x}^{2} + x - 20 = 0.}}$

↪➡$\color{red}{ \bf{ {x}^{2} + 5x - 4x - 20 = 0.}}$

↪➡$\color{red}{ \bf{x(x + 5) - 4(x + 5) = 0.}}$

↪➡$\color{red}{ \bf{(x - 4) \: (x + 5) = 0.}}$

↪➡$\color{red}{ \bf{x - 4 = 0 \: | \: x + 5 = 0.}}$

↪➡$\color{red}{ \boxed{x = 4 \: | \: x = - 5.}}$

↪➡$\color{green}{ \bf{(2). \: 2 {y}^{2} + 27y + 13 = 0.}}$

↪➡$\color{green}{ \bf{2 {y}^{2} + 26y + y + 13 = 0.}}$

↪➡$\color{green}{ \bf{2y(y + 13) + 1(y + 13) = 0.}}$

↪➡$\color{green}{ \bf{(2y + 1) \: (y + 13) = 0.}}$

↪➡$\color{green}{ \bf{2y + 1 = 0 \: | \: y + 13 = 0.}}$

↪➡$\color{green}{ \boxed{y = \frac{ - 1}{2} \: | \: y = - 13.}}$

↪➡$\color{blue}{ \bf{(3). \: 5 {m}^{2} = 22m + 15.}}$

↪➡$\color{blue}{ \bf{5 {m}^{2} - 22m - 15 = 0.}}$

↪➡$\color{blue}{ \bf{5 {m}^{2} - 25m + 3m - 15 = 0.}}$

↪➡$\color{blue}{ \bf{5m(m - 5) + 3(m - 5) = 0.}}$

↪➡$\color{blue}{ \bf{(5m + 3) \: (m - 5) = 0.}}$

↪➡$\color{blue}{ \bf{5m + 3 = 0 \: | \: m - 5 = 0.}}$

↪➡$\color{blue}{ \boxed{m = \frac{ - 3}{5} \: | \: m = 5.}}$

✅✅$\color{grey}{ \boxed{Hence, \: all \: the \: questions \: are \: factorised.}}$✔✔

✴✴$\color{orange}{ \boxed{THANKS}}$✴✴

☺☺☺$\color{gold}{ \bf \underline{Hope \: it \: is \: helpful \: for \: you}}$✌✌✌.