Question

Th cost of 2 table and 8 chair is 2200.If the table cost 150 more than a chair find the cost of each

Answer 1

Let the cost of one table be x
and cost of one chair be y
according to the question
2x + 8y = 2200 (1)
x = y + 150 (2)
put the value of x in (1)
2(y +150) + 8y = 2200
2y + 300 + 8y = 2200
10y = 2200 - 300
10y = 1900
y = 1900/10
y = 190
put y = 190 in (2)
x = 190 + 150
x = 340
SO THE COST OF ONE CHAIR IS ₹190
AND COST OF ONE TABLE IS ₹340

Answer 2

Let the cost of table be $x$ and the cost of chair be $y$. Then using the given information,

$2x+8y=2200\\ x-y=150$

Add 8 times the second equation to the first equation. We get

$10x=2200+8*150\\ 10x=3400\\ x=340\\ y=340-150\\ y=190$

The cost of table is $340$ and that of chair is $190$.