Question

Thanu throws the seed of an eaten mango such that the seed reaches its maximum possible range of 48 m. Determine the maximum height the seed rises to during its travel.(g= 10m/s^2) thiss one

Answer 1

Given :-

Maximum Horizontal Range of seed = 48 m.

Acceleration due to gravity = g = 10 ms-².

To find :

• Maximum height seed rises.

As we know that,

The horizontal range will be maximum, if the angle of Projection is 45°.

R = u² 2SinØ.CosØ/g

48 = u² × 2 × (1/√2)(1/√2)/10

480 = u² × 2 × 1/2

u² = 480

Maximum Height = H = u² Sin²Ø/2g

H = (480 × 1/2)/2 × 10

H = 240/20

H = 12 m.

Hence,

The maximum height = H = 12 m.