Question

the 11th term of an ap exceeds the 4th term by 14? what is the common difference?

Answer 1

Let the first term of AP is "a" and "d" is a common difference then according to question,
a11 - a4 = 14
a + 10d - a - 3d = 14
7d = 14
d = 2

Therefore the common difference is 2.

Answer 2

                a11=a4 +14
            a+10d=a+3d+14
                  7d=14
                    d=2
so the common difference is 2