the 15th term of an A.P is 3 more than twice its 7th term. if the 10th term of the Ap is is 41,find it's nth term
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The nth term is 4(n+1).
Step-by-step explanation:
- a+14 d = 2(a+6 d)+3
a-2d+3=0 -------(1)
Now
a+9 d=41 ------(2)
- Subtracting equation (1) from equation (2)
11 d=44
d=4
- Hence from equation (2)
a = 5
Hence nth term = 5+ (n-1) x 4 =4 n+1
Thus the nth term is 4 n+1.
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