Math, asked by gurvirs992, 5 months ago

the 17 term of AP is 5
more than twice its 9 term. If the 11 term of AP 43 find the no. of terms and the sum of the number

Answers

Answered by anjali983584
0

Step-by-step explanation:

we know that the n th

term of the arithmetic progression is given by a+(n−1)d

Given that the 17 th

term is 5 more than twice the 8 th

term.

Therefore, 5+17 th term=2(8 th term)

⟹a+(17−1)d=2(a+(8−1)d)+5

⟹a+16d−5=2a+14d

⟹a−2d=−5 -------(1)

Given that the 11th term is 43

Therefore, a+(11−1)d=43

⟹a+10d=43 ------(2)

subtracting (1) from (2) we get

(a+10d)−(a−2d)=43−(−5)

⟹12d=48

⟹d=4

⟹a=3

Therefore, the n th term is 3+(n−1)4=4n−1

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