the 24th term of an A.P. is twice its 10th term. Show that its 72nd term is 4 times its 15th term.
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24th term = a + 23d
10th term = a + 18d
a + 23d = 2a + 18d
a = 5d
72th term = a + 71d = 5d + 71d = 76d
15th term = (a + 14d)
= (a + 14d) = 5d + 14d
= 19d * 4
= 76 d
10th term = a + 18d
a + 23d = 2a + 18d
a = 5d
72th term = a + 71d = 5d + 71d = 76d
15th term = (a + 14d)
= (a + 14d) = 5d + 14d
= 19d * 4
= 76 d
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