the 4th term of an ap is 3 times the first and the Seven terms exceeds twice the third term buy 1. find the first term at the common difference
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a4=a+3d
a+3d=3a
2a=3d
a=3/2d
a7=a+6d
a+6d+1=a+2d
4d=-1
d=-1/4
a=3/2×-1/4
a=-3/8
a+3d=3a
2a=3d
a=3/2d
a7=a+6d
a+6d+1=a+2d
4d=-1
d=-1/4
a=3/2×-1/4
a=-3/8
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