The 6th and 17th term and 19 and 41 respectively find 40
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Answer:
166.32 is the answer
Step-by-step explanation:
t of 6 = 19
t of 17 = 41
but t of 6= a+(n-1)d t of 17 = a+(n+1)d
19 = a+5d ...(1) 41 = a+16d ...... (2)
a= 5d-19
put a= 5d-19 in equation (2)
41= a+16d
41= 5d-19+16d
41+19=21d
60 = 21d
60÷21=d
30÷7=d
4.28 = d
substitute d= 4.28 in equation (1)
a+5d=19
a+5(4.28)=19
a+ 21.40 = 19
a= 19- 21.4
a = 2.4
we have t of n = a+(n+1)d
t of 40=2.4+(39)4.28
t of 40=2.4+163.92
t of 40= 166.32
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