The 6th term and 7th term of an ap are 19 and 41 respectively . Find the 40th term
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Answered by
17
7th term => a + 6d
41 = a + 6d
41 - 6d = a ---1equation
======================
6th term = a + 5d
19 = 41 - 6d + 5d
6d - 5d = 41 - 19
d = 22
Putting the value of d in 1equation
a = 41 - 6(22)
a = 41 - 132
a = -91
=====================
40th term = a + 39d
=> -91 + 39(22)
=> -91 + 858
=> 767
I hope this will help you
(-:
41 = a + 6d
41 - 6d = a ---1equation
======================
6th term = a + 5d
19 = 41 - 6d + 5d
6d - 5d = 41 - 19
d = 22
Putting the value of d in 1equation
a = 41 - 6(22)
a = 41 - 132
a = -91
=====================
40th term = a + 39d
=> -91 + 39(22)
=> -91 + 858
=> 767
I hope this will help you
(-:
Answered by
6
Hey! Here is ur answer...
We have used the formula :-
nth term of an AP = a + (n - 1) d
Hope it will help u... Plz mark it as brainliest... :)
We have used the formula :-
nth term of an AP = a + (n - 1) d
Hope it will help u... Plz mark it as brainliest... :)
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