Question

The 8 th term from the end of an AP -12,-9,-6,.............5, is ______.​

Answer 1

Step-by-step explanation:

A.P.: -12, -9, -6,..........5.

on reversing the order of A.P.

now,

A.P.: 5, ........,-6, -9, -12.

first term, a=5

common difference, d= (-9)-(-6) = -3

term 8 = a+ (n-1)d

= 5 +(8-1)-3

=5-21

= -16

The 8th term from the end of A.P. is -16.

Answer 2

Step-by-step explanation:

A.p_-12,-9,-6,.....5

first term=-12

common difference =[-9-(-12)]=3

n=8

t8=2a(n-1)d

=2(-12)(8-1)3

=-24×21

=-3

t8=-3