Question

The acceleration due to gravity on a planet is 1.96 m/s2. if it is safe to jump from a height of 3 m on the earth, the corresponding height on the planet will be

Answer 1

We know that

V^2-U^2=2as

From there .....

We get V^2 =60

(Taking a=10ms^-2,S=3m ,U=0)

..Now 2nd case...

Again apply that formula..

(Given g=1.96ms^-2 )

As we get V^2 =60ms^-1

S=60÷(2×1.96)

S=15m(ans)

Answer 2

Answer:

15 m

Step-by-step explanation:

Let's have a look at the issue.

Let u=0 be the initial velocity.

The final speed will be v

Gravitational acceleration g=9.8m/s 2

The vertical distance is equal to 3 metres.

v²-u²=2gs

v²-0=2*9.5*3

=7.7m/s

On the planet so,

v²-0=2*1.96*h

Let's suppose v = 7.7m/s

then,

58.8/2×1.96

= 15 m

As a result, the equivalent height on the planet will be =15m.

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