The accuracy of a clock is one part in 10°. The maximum error when a clock is operating for 1010 s is
O 15
O 10 s
O 0.1 s
O 0.001 s
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Given : accuracy of a clock is one part in 10⁹
To Find : The maximum error when a clock is operating for 10¹⁰
Solution:
accuracy of a clock is one part in 10⁹
Error in 1 sec will be 1/10⁹
Error in 10¹⁰ secs will be = 10¹⁰ x 1/10⁹
=> Error in 10¹⁰ secs will be = 10 sec
The maximum error when a clock is operating for 10¹⁰ secs is 10 sec
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