The adjacent angels of a parallelogram are x° and (2x+30)°. Find all the angles of the parallelogram.
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X(x+30)=180,3x=150, x=150/3=50 then x=50 and (2×40+30)=180 in the parallelogram opposite angles are equal
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9
Let ABCD is a parallelogram .
<A = x° , <B = 2x + 30
<A + <B = 180°
[ Sum of adjacent angles are supplementary ]
x + 2x + 30 = 180°
=> 3x = 180- 30
=> 3x = 150
x = 150/3
x = 50
Therefore,
<A = x° = 50°
<B = 2x + 30 = 2×50 + 30 = 130°
<A = <C = x° = 50°
<B = <D = 130°
[ Opposite angles are equal ]
***
<A = x° , <B = 2x + 30
<A + <B = 180°
[ Sum of adjacent angles are supplementary ]
x + 2x + 30 = 180°
=> 3x = 180- 30
=> 3x = 150
x = 150/3
x = 50
Therefore,
<A = x° = 50°
<B = 2x + 30 = 2×50 + 30 = 130°
<A = <C = x° = 50°
<B = <D = 130°
[ Opposite angles are equal ]
***
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