Question

The adjacent sides of a parallelogram are 15cm and 8cm.lf the distance between the longer sides is 4cm,find the distance between the shorter sides ​

Answer 1

Answer:

$area \: of \: parallelogram =ah1 \: or \: bh2 \\ longer \: side \times height \: 1 \: or \: shorter \: side \\ \times height \: 2\\ area = 15cm \times 4cm = 60 {cm}^{2} \\ area</p><p> = 8cm \times x = 60 {cm}^{2} \\ x = \frac{60 {cm}^{2} }{8cm} = 7.5cm \\ height \: of \: the \: parallelogram \: is \: 7.5cm.$

Answer 2

Step-by-step explanation:

The larger side = 15cm

the opposite side of base = 15cm

height or distance between two sides =4cm

Area of llgm =b×h

=15×4

=60cm^2

Area with shorter side as base=60cm^2

=

-> b×h = 60cm^2

-> 15h= 60

-> h=60/15

-> h= 4 cm

distance between shorter sides = 4cm