Question

the adjoining figure, A ABC is an isosceles triangle in which
respectively, prove that BE = CF.
AB = AC. If E and F be the midpoints of AC and AB
Hint. Show that ABCF = ACBE.​

Answer 1

Answer:

ab - bc _______ (1)

and b = c _______(2)

here e and f are midpoints of ac and ab

respectively

af = fb and ae = ec

know ab = bc

af + fb = ae + ec

2af = 2ae

af = ae

af = fb = ae = ec _________(3)

in Δ bcf and Δ cbe

bc = bc (common side)

b = c (from (2) )

bf = bc (from (3) )

by sas condition for congruency

Δ bcf ~ Δ cbe

since Δ bcf ~ Δ cbe by properley of congruncy we can with that be = cf