the adjoining figure shows a parallelogram abcd in which p is the midpoint of ab and q is the midpoint of cd prove that ae=ef=fc
Answers
Answered by
2
Step-by-step explanation:
ANSWER
Since E and F are mid-points AB and CD respectively.
∴AE=BE=
2
1
AB and CF=DF=
2
1
CD
But, AB=CD
∴
2
1
AB=
2
1
CD⇒BE=CF
Also, BE∥CF [∵AB∥CD]
∴ BEFC is a parallelogram.
⇒BC∥EF and BE=PH ...(i)
Now, BC∥EF
⇒AD∥EF [∵BC∥AD as ABCD is a ∥
gm
]
⇒AEFD is a parallelogram
⇒AE=GP ...(ii)
But, E is the mid-point of AB.
∴AE=BE
⇒GP=PH [Using (i) and (ii)]
solution
Answered By
toppr
95 Views
How satisfied are you with the answer?
This will help us to improve better
answr
Get Instant Solutions, 24x7
No Signup required
girl
More Questions by difficulty
EASY
MEDIUM
HARD
Prev Question
Next Question
Similar questions