the adjoining figure shows that ac=bd if ab=cd
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Given,
AC=BD ... (i)
AC=AB+BC ……(ii) (Point B lies between A and C)
BD=BC+CD … (iii) (Point C lies between B and D)
Now,
substituting (ii) and (iii) in (i), we get
⇒AB+BC=BC+CD
⇒AB+BC–BC=CD
⇒AB=CD
Hence, AB=CD.
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