The age of a father is 5 years mire than the age of 6 times of his son's age. After 7 years the age of father will be 3 more than his son's age. Find their present ages.
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Let the age of the son be x
So the age of father = 6x+5
After 7 years the ave of son = x+7
Fathers's age=6x+5+7
The age of father is 3 time so=
3(x+7)
now we will solve
3(x+7)=6x+5+7
3x+21=6x+12
12-21=6x-3x(by t.p)
9=3x
X= 9÷3
X=3
So that time the age of son was 3
So now 3+7=10
The presant age of son = 10
And the presant age of father = 6x3+12=
18+12=30
So yhe present age of son and father
10 and 30
So the age of father = 6x+5
After 7 years the ave of son = x+7
Fathers's age=6x+5+7
The age of father is 3 time so=
3(x+7)
now we will solve
3(x+7)=6x+5+7
3x+21=6x+12
12-21=6x-3x(by t.p)
9=3x
X= 9÷3
X=3
So that time the age of son was 3
So now 3+7=10
The presant age of son = 10
And the presant age of father = 6x3+12=
18+12=30
So yhe present age of son and father
10 and 30
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