Math, asked by kulkarnisanjay7347, 1 year ago

The age of a man is twice the square of the age of his son. Eight years hence, the age of the man will be 4 years more than three times the age of his son. Find their present ages.Dear expert please solve it by two cases First take man's age = x then second case son's age = x

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Answered by TheUrvashi

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hope it helps to you

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