Math, asked by souvik5319, 1 year ago

The age of reena and teena are in the ratio 3:4.five years ago thier ages were in the ratio 2:3.find thier present ages.

Answers

Answered by Anonymous
3
Hiii!!!

Here's Ur answer...

Given the ratio between the age of Reena and Teena is 3 : 4

Let their age be 3x and 4x respectively.

5 years ago, the ratio between their age was 2 : 3

Therefore 3x - 5/ 4x - 5 = 2/3

==> 3 ( 3x - 5 ) = 2 ( 4x - 5 )

==> 9x - 15 = 8x - 10

==> 9x - 8x = -10 + 15

==> x = 5

Hence, present age of Reena = 3x

= 3 × 5

= 15yrs

Present age of teena = 4x

= 4 × 5

= 20yrs

Hope this helps..!!
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