Question

The age of the father 3 yrs ago was 7 times the age of his son. at present the father's age is 5 times that of his son. what are the present ages of the father and the son ?

Answer 1

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Answer 2

3 YEARS AGO

let age of son be x
age of father is 7x

PRESENT AGES (we must ad 3 because 3 years after past is present)
age of son = x+3
age of father = 5(x+3) = 5x + 15

past age + 3 = present age
father past age = 7x
acc to past fathers present age is 7x+3
fathers present age (given in the question) = 5x + 15

if we equate both the given ages of father,
7x + 3 = 5x + 15
7x - 5x = 15 - 3
2x = 12
x = 12/2
x = 6

therefore,
son past age = x = 6 years
fathers past age 7x = 42 years

son present age = x + 3 = 9 years
fathers present age = 45 years

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