Question

The ages of A and B are in ratio 7:5. Ten years hence,the ratio of their ages will be 9:7. find their present ages

Answer 1

Heya...
Here is your answer ----

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Let the age of A be 7x

Let the age of B be 5x
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ATQ -----
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=> (7x + 10) : (5x + 10) = 9 : 7

=> (7x + 10) / (5x + 10) = 9 / 7

=> 7 (7x + 10) = 9 (5x + 10) [Cross multiplication)

=> 49x + 70 = 45x + 90

=> 49x - 45x = 90 - 70

=> 4x = 20

=> x = 20 / 4

=> x = 5
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• A's present age = 7x = (7×5) years = 35 years

• B's present age = 5x = (5×5) years = 25 years
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HOPE IT HELPS....!!!

Answer 2

Answer:                                                                      

Present Age of A =35

Present Age of B =25

Step-by-step explanation:

Let the Present ages ofA and B be 7x and 5x respectively.

After 10 years, their ages will be (7x +10) and (5x + 10)

Given

(7x +10) : (5x + 10) = 9 : 7

⇒7(7x + 10)= 9(5x + 10)    Product of extremes = Product of means

⇒49x+ 70= 45x + 90

⇒49x - 45x = 90-70

⇒4x= 20

⇒x=20/4

⇒x=5

∴Age of A = 7x = 7 x 5 =35

Age of B = 5x = 5 x 5 =25

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